Base | Representation |
---|---|
bin | 1001000011100000100… |
… | …01010100001001000011 |
3 | 1002202001120111011122022 |
4 | 10201300101110021003 |
5 | 20044134013414301 |
6 | 354532131432055 |
7 | 31322605561511 |
oct | 4416021241103 |
9 | 1082046434568 |
10 | 311121232451 |
11 | 10aa449088a7 |
12 | 50369a5562b |
13 | 23452bc2123 |
14 | 110b616d4b1 |
15 | 815dbe8d1b |
hex | 4870454243 |
311121232451 has 4 divisors (see below), whose sum is σ = 311802023352. Its totient is φ = 310440441552.
The previous prime is 311121232427. The next prime is 311121232489. The reversal of 311121232451 is 154232121113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 311121232451 - 214 = 311121216067 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 311121232451.
It is not an unprimeable number, because it can be changed into a prime (311121232351) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 340394765 + ... + 340395678.
It is an arithmetic number, because the mean of its divisors is an integer number (77950505838).
Almost surely, 2311121232451 is an apocalyptic number.
311121232451 is a deficient number, since it is larger than the sum of its proper divisors (680790901).
311121232451 is an equidigital number, since it uses as much as digits as its factorization.
311121232451 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 680790900.
The product of its digits is 1440, while the sum is 26.
Adding to 311121232451 its reverse (154232121113), we get a palindrome (465353353564).
The spelling of 311121232451 in words is "three hundred eleven billion, one hundred twenty-one million, two hundred thirty-two thousand, four hundred fifty-one".
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