Base | Representation |
---|---|
bin | 1001000011100000100… |
… | …01100100101011111111 |
3 | 1002202001120121121121101 |
4 | 10201300101210223333 |
5 | 20044134023101343 |
6 | 354532133113531 |
7 | 31322606263216 |
oct | 4416021445377 |
9 | 1082046547541 |
10 | 311121300223 |
11 | 10aa44954808 |
12 | 50369a888a7 |
13 | 23452c16c26 |
14 | 110b618a07d |
15 | 815dc0de4d |
hex | 4870464aff |
311121300223 has 2 divisors, whose sum is σ = 311121300224. Its totient is φ = 311121300222.
The previous prime is 311121300211. The next prime is 311121300239. The reversal of 311121300223 is 322003121113.
It is a weak prime.
It is an emirp because it is prime and its reverse (322003121113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 311121300223 - 29 = 311121299711 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 311121300223.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311121300323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155560650111 + 155560650112.
It is an arithmetic number, because the mean of its divisors is an integer number (155560650112).
Almost surely, 2311121300223 is an apocalyptic number.
311121300223 is a deficient number, since it is larger than the sum of its proper divisors (1).
311121300223 is an equidigital number, since it uses as much as digits as its factorization.
311121300223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 311121300223 its reverse (322003121113), we get a palindrome (633124421336).
The spelling of 311121300223 in words is "three hundred eleven billion, one hundred twenty-one million, three hundred thousand, two hundred twenty-three".
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