3111213010183 has 2 divisors, whose sum is σ = 3111213010184. Its totient is φ = 3111213010182.

The previous prime is 3111213010177. The next prime is 3111213010223. The reversal of 3111213010183 is 3810103121113.

3111213010183 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (3810103121113) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3111213010183 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3111213010133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555606505091 + 1555606505092.

It is an arithmetic number, because the mean of its divisors is an integer number (1555606505092).

Almost surely, 2^{3111213010183} is an apocalyptic number.

3111213010183 is a deficient number, since it is larger than the sum of its proper divisors (1).

3111213010183 is an equidigital number, since it uses as much as digits as its factorization.

3111213010183 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 25.

Adding to 3111213010183 its reverse (3810103121113), we get a palindrome (6921316131296).

The spelling of 3111213010183 in words is "three trillion, one hundred eleven billion, two hundred thirteen million, ten thousand, one hundred eighty-three".