31112130113 has 2 divisors, whose sum is σ = 31112130114. Its totient is φ = 31112130112.

The previous prime is 31112130079. The next prime is 31112130143. The reversal of 31112130113 is 31103121113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 30915485584 + 196644529 = 175828^2 + 14023^2 .

It is a cyclic number.

It is not a de Polignac number, because 31112130113 - 2¹⁰ = 31112129089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 31112130091 and 31112130100.

It is not a weakly prime, because it can be changed into another prime (31112130143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15556065056 + 15556065057.

It is an arithmetic number, because the mean of its divisors is an integer number (15556065057).

Almost surely, 2^31112130113 is an apocalyptic number.

It is an amenable number.

31112130113 is a deficient number, since it is larger than the sum of its proper divisors (1).

31112130113 is an equidigital number, since it uses as much as digits as its factorization.

31112130113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 31112130113 its reverse (31103121113), we get a palindrome (62215251226).

The spelling of 31112130113 in words is "thirty-one billion, one hundred twelve million, one hundred thirty thousand, one hundred thirteen".