Base | Representation |
---|---|
bin | 1110001001011110110111… |
… | …01001011111001101011101 |
3 | 11002011021212001112111200001 |
4 | 13010233123221133031131 |
5 | 13034220122100222343 |
6 | 150100414445334301 |
7 | 6360530443613533 |
oct | 704573351371535 |
9 | 132137761474601 |
10 | 31112133210973 |
11 | 9a05644119031 |
12 | 35a58a6567391 |
13 | 1448b27b501a9 |
14 | 797b9a02a153 |
15 | 38e470a6044d |
hex | 1c4bdba5f35d |
31112133210973 has 2 divisors, whose sum is σ = 31112133210974. Its totient is φ = 31112133210972.
The previous prime is 31112133210913. The next prime is 31112133211007. The reversal of 31112133210973 is 37901233121113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 28330102695609 + 2782030515364 = 5322603^2 + 1667942^2 .
It is a cyclic number.
It is not a de Polignac number, because 31112133210973 - 229 = 31111596340061 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31112133210913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15556066605486 + 15556066605487.
It is an arithmetic number, because the mean of its divisors is an integer number (15556066605487).
Almost surely, 231112133210973 is an apocalyptic number.
It is an amenable number.
31112133210973 is a deficient number, since it is larger than the sum of its proper divisors (1).
31112133210973 is an equidigital number, since it uses as much as digits as its factorization.
31112133210973 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20412, while the sum is 37.
The spelling of 31112133210973 in words is "thirty-one trillion, one hundred twelve billion, one hundred thirty-three million, two hundred ten thousand, nine hundred seventy-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •