Base | Representation |
---|---|
bin | 101101010001100011001… |
… | …010011011010100110011 |
3 | 102000102121021022200021021 |
4 | 231101203022123110303 |
5 | 401433234310000201 |
6 | 10341135202040311 |
7 | 440530634442022 |
oct | 55214312332463 |
9 | 12012537280237 |
10 | 3111220000051 |
11 | a9a508642999 |
12 | 422b85349097 |
13 | 197504a04717 |
14 | aa8261348b9 |
15 | 55de39c7ea1 |
hex | 2d46329b533 |
3111220000051 has 2 divisors, whose sum is σ = 3111220000052. Its totient is φ = 3111220000050.
The previous prime is 3111219999991. The next prime is 3111220000067. The reversal of 3111220000051 is 1500000221113.
3111220000051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an a-pointer prime, because the next prime (3111220000067) can be obtained adding 3111220000051 to its sum of digits (16).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3111220000051 - 241 = 912196744499 is a prime.
It is not a weakly prime, because it can be changed into another prime (3111220700051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555610000025 + 1555610000026.
It is an arithmetic number, because the mean of its divisors is an integer number (1555610000026).
Almost surely, 23111220000051 is an apocalyptic number.
3111220000051 is a deficient number, since it is larger than the sum of its proper divisors (1).
3111220000051 is an equidigital number, since it uses as much as digits as its factorization.
3111220000051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60, while the sum is 16.
Adding to 3111220000051 its reverse (1500000221113), we get a palindrome (4611220221164).
The spelling of 3111220000051 in words is "three trillion, one hundred eleven billion, two hundred twenty million, fifty-one", and thus it is an aban number.
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