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3111220000051 is a prime number
BaseRepresentation
bin101101010001100011001…
…010011011010100110011
3102000102121021022200021021
4231101203022123110303
5401433234310000201
610341135202040311
7440530634442022
oct55214312332463
912012537280237
103111220000051
11a9a508642999
12422b85349097
13197504a04717
14aa8261348b9
1555de39c7ea1
hex2d46329b533

3111220000051 has 2 divisors, whose sum is σ = 3111220000052. Its totient is φ = 3111220000050.

The previous prime is 3111219999991. The next prime is 3111220000067. The reversal of 3111220000051 is 1500000221113.

3111220000051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an a-pointer prime, because the next prime (3111220000067) can be obtained adding 3111220000051 to its sum of digits (16).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 3111220000051 - 241 = 912196744499 is a prime.

It is not a weakly prime, because it can be changed into another prime (3111220700051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555610000025 + 1555610000026.

It is an arithmetic number, because the mean of its divisors is an integer number (1555610000026).

Almost surely, 23111220000051 is an apocalyptic number.

3111220000051 is a deficient number, since it is larger than the sum of its proper divisors (1).

3111220000051 is an equidigital number, since it uses as much as digits as its factorization.

3111220000051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 16.

Adding to 3111220000051 its reverse (1500000221113), we get a palindrome (4611220221164).

The spelling of 3111220000051 in words is "three trillion, one hundred eleven billion, two hundred twenty million, fifty-one", and thus it is an aban number.