Search a number
-
+
311130013112100 = 22325271337923911113
BaseRepresentation
bin100011010111110001001100…
…1111010010001011100100100
31111210121201221120012200012200
41012233202121322101130210
5311240023231324041400
63021415053240014500
7122351254524121440
oct10657423172213444
91453551846180180
10311130013112100
1190154552293906
122aa8b0b7a61430
131047b585341920
1456b8ab70cb820
1525e83140bbb00
hex11af899e91724

311130013112100 has 864 divisors, whose sum is σ = 1232954554191360. Its totient is φ = 63858164244480.

The previous prime is 311130013112099. The next prime is 311130013112153. The reversal of 311130013112100 is 1211310031113.

311130013112100 is a `hidden beast` number, since 3 + 11 + 130 + 0 + 1 + 311 + 210 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 287 ways as a sum of consecutive naturals, for example, 27996936144 + ... + 27996947256.

Almost surely, 2311130013112100 is an apocalyptic number.

311130013112100 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 311130013112100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (616477277095680).

311130013112100 is an abundant number, since it is smaller than the sum of its proper divisors (921824541079260).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

311130013112100 is a wasteful number, since it uses less digits than its factorization.

311130013112100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20429 (or 20419 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 18.

Adding to 311130013112100 its reverse (1211310031113), we get a palindrome (312341323143213).

It can be divided in two parts, 311130013 and 112100, that added together give a palindrome (311242113).

The spelling of 311130013112100 in words is "three hundred eleven trillion, one hundred thirty billion, thirteen million, one hundred twelve thousand, one hundred".