3111303113 has 2 divisors, whose sum is σ = 3111303114. Its totient is φ = 3111303112.

The previous prime is 3111303089. The next prime is 3111303179. The reversal of 3111303113 is 3113031113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1946309689 + 1164993424 = 44117^2 + 34132^2 .

It is a cyclic number.

It is not a de Polignac number, because 3111303113 - 2⁶ = 3111303049 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 3111303091 and 3111303100.

It is not a weakly prime, because it can be changed into another prime (3111303913) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555651556 + 1555651557.

It is an arithmetic number, because the mean of its divisors is an integer number (1555651557).

Almost surely, 2^3111303113 is an apocalyptic number.

It is an amenable number.

3111303113 is a deficient number, since it is larger than the sum of its proper divisors (1).

3111303113 is an equidigital number, since it uses as much as digits as its factorization.

3111303113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81, while the sum is 17.

The square root of 3111303113 is about 55779.0562218473. The cubic root of 3111303113 is about 1459.8697439620.

Adding to 3111303113 its reverse (3113031113), we get a palindrome (6224334226).

Subtracting 3111303113 from its reverse (3113031113), we obtain a cube (1728000 = 120³).

The spelling of 3111303113 in words is "three billion, one hundred eleven million, three hundred three thousand, one hundred thirteen".