31113031231 has 4 divisors (see below), whose sum is σ = 31124787952. Its totient is φ = 31101274512.

The previous prime is 31113031207. The next prime is 31113031303. The reversal of 31113031231 is 13213031113.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 31113031231 - 2⁵ = 31113031199 is a prime.

It is a super-2 number, since 2×31113031231² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 31113031199 and 31113031208.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31113031531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5874390 + ... + 5879683.

It is an arithmetic number, because the mean of its divisors is an integer number (7781196988).

Almost surely, 2^31113031231 is an apocalyptic number.

31113031231 is a deficient number, since it is larger than the sum of its proper divisors (11756721).

31113031231 is a wasteful number, since it uses less digits than its factorization.

31113031231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11756720.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 31113031231 its reverse (13213031113), we get a palindrome (44326062344).

The spelling of 31113031231 in words is "thirty-one billion, one hundred thirteen million, thirty-one thousand, two hundred thirty-one".