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31113103100230 = 2521114745546493
BaseRepresentation
bin1110001001100000101010…
…11101010100100101000110
311002011101100122112222121101
413010300111131110211012
513034224113343201410
6150101055013410314
76360563461545154
oct704602535244506
9132141318488541
1031113103100230
119a05aa16461a8
1235a5b1733999a
131448c50a76b68
14797c4cb7a3d4
1538e4cac94d3a
hex1c4c15754946

31113103100230 has 16 divisors (see below), whose sum is σ = 56269005421104. Its totient is φ = 12386259053280.

The previous prime is 31113103100161. The next prime is 31113103100239. The reversal of 31113103100230 is 3200130131113.

It is a junction number, because it is equal to n+sod(n) for n = 31113103100198 and 31113103100207.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31113103100239) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7372771137 + ... + 7372775356.

It is an arithmetic number, because the mean of its divisors is an integer number (3516812838819).

Almost surely, 231113103100230 is an apocalyptic number.

31113103100230 is a deficient number, since it is larger than the sum of its proper divisors (25155902320874).

31113103100230 is a wasteful number, since it uses less digits than its factorization.

31113103100230 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14745546711.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 31113103100230 its reverse (3200130131113), we get a palindrome (34313233231343).

The spelling of 31113103100230 in words is "thirty-one trillion, one hundred thirteen billion, one hundred three million, one hundred thousand, two hundred thirty".

Divisors: 1 2 5 10 211 422 1055 2110 14745546493 29491092986 73727732465 147455464930 3111310310023 6222620620046 15556551550115 31113103100230