Base | Representation |
---|---|
bin | 100011010111110001110000… |
… | …0101011000100101101101011 |
3 | 1111210121212000022010120201211 |
4 | 1012233203200223010231223 |
5 | 311240033144234410443 |
6 | 3021415411125453551 |
7 | 122351326121130244 |
oct | 10657434053045553 |
9 | 1453555008116654 |
10 | 311131200310123 |
11 | 901550014462a6 |
12 | 2aa8b3895712b7 |
13 | 1047b7142a306b |
14 | 56b8b8aa47ccb |
15 | 25e838342919d |
hex | 11af8e0ac4b6b |
311131200310123 has 2 divisors, whose sum is σ = 311131200310124. Its totient is φ = 311131200310122.
The previous prime is 311131200310093. The next prime is 311131200310157. The reversal of 311131200310123 is 321013002131113.
It is a weak prime.
It is an emirp because it is prime and its reverse (321013002131113) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-311131200310123 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 311131200310094 and 311131200310103.
It is not a weakly prime, because it can be changed into another prime (311131200310823) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155565600155061 + 155565600155062.
It is an arithmetic number, because the mean of its divisors is an integer number (155565600155062).
Almost surely, 2311131200310123 is an apocalyptic number.
311131200310123 is a deficient number, since it is larger than the sum of its proper divisors (1).
311131200310123 is an equidigital number, since it uses as much as digits as its factorization.
311131200310123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 311131200310123 its reverse (321013002131113), we get a palindrome (632144202441236).
The spelling of 311131200310123 in words is "three hundred eleven trillion, one hundred thirty-one billion, two hundred million, three hundred ten thousand, one hundred twenty-three".
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