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3111312201157 is a prime number
BaseRepresentation
bin101101010001101000101…
…010001001010111000101
3102000102211200210222102001
4231101220222021113011
5401433431410414112
610341152254145301
7440533134232636
oct55215052112705
912012750728361
103111312201157
11a9a555697a56
12422bb01b2231
1319751ab474a4
14aa83449588d
1555debb3bc57
hex2d468a895c5

3111312201157 has 2 divisors, whose sum is σ = 3111312201158. Its totient is φ = 3111312201156.

The previous prime is 3111312201139. The next prime is 3111312201287. The reversal of 3111312201157 is 7511022131113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2533703081121 + 577609120036 = 1591761^2 + 760006^2 .

It is a cyclic number.

It is not a de Polignac number, because 3111312201157 - 215 = 3111312168389 is a prime.

It is a super-2 number, since 2×31113122011572 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3111312201457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555656100578 + 1555656100579.

It is an arithmetic number, because the mean of its divisors is an integer number (1555656100579).

Almost surely, 23111312201157 is an apocalyptic number.

It is an amenable number.

3111312201157 is a deficient number, since it is larger than the sum of its proper divisors (1).

3111312201157 is an equidigital number, since it uses as much as digits as its factorization.

3111312201157 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1260, while the sum is 28.

The spelling of 3111312201157 in words is "three trillion, one hundred eleven billion, three hundred twelve million, two hundred one thousand, one hundred fifty-seven".