Base | Representation |
---|---|
bin | 1110001001100000101101… |
… | …00101111010110010101001 |
3 | 11002011101101222100212001220 |
4 | 13010300112211322302221 |
5 | 13034224133231143423 |
6 | 150101100533332253 |
7 | 6360564112366611 |
oct | 704602645726251 |
9 | 132141358325056 |
10 | 31113122131113 |
11 | 9a06001364400 |
12 | 35a5b21797089 |
13 | 1448c549ab139 |
14 | 797c514d1a41 |
15 | 38e4cc7a39e3 |
hex | 1c4c1697aca9 |
31113122131113 has 96 divisors (see below), whose sum is σ = 46624760759808. Its totient is φ = 18436830382080.
The previous prime is 31113122131103. The next prime is 31113122131181.
31113122131113 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 31113122131113 - 222 = 31113117936809 is a prime.
It is not an unprimeable number, because it can be changed into a prime (31113122131103) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 2806265056 + ... + 2806276142.
It is an arithmetic number, because the mean of its divisors is an integer number (485674591248).
Almost surely, 231113122131113 is an apocalyptic number.
31113122131113 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
It is an amenable number.
31113122131113 is a deficient number, since it is larger than the sum of its proper divisors (15511638628695).
31113122131113 is a wasteful number, since it uses less digits than its factorization.
31113122131113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12095 (or 12084 counting only the distinct ones).
The product of its digits is 324, while the sum is 24.
It can be divided in two parts, 3111312 and 2131113, that added together give a palindrome (5242425).
The spelling of 31113122131113 in words is "thirty-one trillion, one hundred thirteen billion, one hundred twenty-two million, one hundred thirty-one thousand, one hundred thirteen".
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