Base | Representation |
---|---|
bin | 1110001001100000101110… |
… | …10000001001001001101111 |
3 | 11002011101102202012012201001 |
4 | 13010300113100021021233 |
5 | 13034224144044344413 |
6 | 150101102010501131 |
7 | 6360564305440432 |
oct | 704602720111157 |
9 | 132141382165631 |
10 | 31113133199983 |
11 | 9a0600763462a |
12 | 35a5b254347a7 |
13 | 1448c57085373 |
14 | 797c52b73819 |
15 | 38e4cd73d4dd |
hex | 1c4c1740926f |
31113133199983 has 2 divisors, whose sum is σ = 31113133199984. Its totient is φ = 31113133199982.
The previous prime is 31113133199969. The next prime is 31113133200031. The reversal of 31113133199983 is 38999133131113.
It is a weak prime.
It is an emirp because it is prime and its reverse (38999133131113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31113133199983 - 217 = 31113133068911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31113133199923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15556566599991 + 15556566599992.
It is an arithmetic number, because the mean of its divisors is an integer number (15556566599992).
Almost surely, 231113133199983 is an apocalyptic number.
31113133199983 is a deficient number, since it is larger than the sum of its proper divisors (1).
31113133199983 is an equidigital number, since it uses as much as digits as its factorization.
31113133199983 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1417176, while the sum is 55.
The spelling of 31113133199983 in words is "thirty-one trillion, one hundred thirteen billion, one hundred thirty-three million, one hundred ninety-nine thousand, nine hundred eighty-three".
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