31113201202331 has 4 divisors (see below), whose sum is σ = 31113360961200. Its totient is φ = 31113041443464.

The previous prime is 31113201202309. The next prime is 31113201202339. The reversal of 31113201202331 is 13320210231113.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-31113201202331 is a prime.

It is a super-2 number, since 2×31113201202331² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 31113201202297 and 31113201202306.

It is not an unprimeable number, because it can be changed into a prime (31113201202339) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79586951 + ... + 79976928.

It is an arithmetic number, because the mean of its divisors is an integer number (7778340240300).

Almost surely, 2^{31113201202331} is an apocalyptic number.

31113201202331 is a deficient number, since it is larger than the sum of its proper divisors (159758869).

31113201202331 is a wasteful number, since it uses less digits than its factorization.

31113201202331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 159758868.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 31113201202331 its reverse (13320210231113), we get a palindrome (44433411433444).

The spelling of 31113201202331 in words is "thirty-one trillion, one hundred thirteen billion, two hundred one million, two hundred two thousand, three hundred thirty-one".