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31113222013 = 311003652323
BaseRepresentation
bin11100111110011111…
…100001011101111101
32222022100000102220001
4130332133201131331
51002204441101023
622143200154301
72151005011036
oct347637413575
988270012801
1031113222013
111221666a225
126043908991
132c1abc5053
141712229a8d
15c217226ad
hex73e7e177d

31113222013 has 4 divisors (see below), whose sum is σ = 32116874368. Its totient is φ = 30109569660.

The previous prime is 31113221999. The next prime is 31113222017. The reversal of 31113222013 is 31022231113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31022231113 = 110927973157.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-31113222013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31113222017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 501826131 + ... + 501826192.

It is an arithmetic number, because the mean of its divisors is an integer number (8029218592).

Almost surely, 231113222013 is an apocalyptic number.

It is an amenable number.

31113222013 is a deficient number, since it is larger than the sum of its proper divisors (1003652355).

31113222013 is a wasteful number, since it uses less digits than its factorization.

31113222013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1003652354.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 31113222013 its reverse (31022231113), we get a palindrome (62135453126).

The spelling of 31113222013 in words is "thirty-one billion, one hundred thirteen million, two hundred twenty-two thousand, thirteen".

Divisors: 1 31 1003652323 31113222013