Base | Representation |
---|---|
bin | 1110001001100000111010… |
… | …00110000110010100010110 |
3 | 11002011101200120122122220221 |
4 | 13010300131012012110112 |
5 | 13034224344143331410 |
6 | 150101115431544554 |
7 | 6360566605620052 |
oct | 704603506062426 |
9 | 132141616578827 |
10 | 31113231230230 |
11 | 9a06057a00166 |
12 | 35a5b5222b15a |
13 | 1448c71489426 |
14 | 797c61bb0c62 |
15 | 38e4d71544da |
hex | 1c4c1d186516 |
31113231230230 has 64 divisors (see below), whose sum is σ = 57850711349760. Its totient is φ = 12035434982400.
The previous prime is 31113231230173. The next prime is 31113231230231. The reversal of 31113231230230 is 3203213231113.
It is a junction number, because it is equal to n+sod(n) for n = 31113231230195 and 31113231230204.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31113231230231) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4019274160 + ... + 4019281900.
It is an arithmetic number, because the mean of its divisors is an integer number (903917364840).
Almost surely, 231113231230230 is an apocalyptic number.
31113231230230 is a deficient number, since it is larger than the sum of its proper divisors (26737480119530).
31113231230230 is a wasteful number, since it uses less digits than its factorization.
31113231230230 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15145.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 31113231230230 its reverse (3203213231113), we get a palindrome (34316444461343).
The spelling of 31113231230230 in words is "thirty-one trillion, one hundred thirteen billion, two hundred thirty-one million, two hundred thirty thousand, two hundred thirty".
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