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31113312211213 is a prime number
BaseRepresentation
bin1110001001100001000011…
…11011000001000100001101
311002011101220020000220221121
413010300201323001010031
513034230030411224323
6150101131443400541
76360601611140161
oct704604173010415
9132141806026847
1031113312211213
119a060996913a1
1235a5b75383151
131448c851a117b
14797c6c850ca1
1538e4de2eda5d
hex1c4c21ec110d

31113312211213 has 2 divisors, whose sum is σ = 31113312211214. Its totient is φ = 31113312211212.

The previous prime is 31113312211181. The next prime is 31113312211283. The reversal of 31113312211213 is 31211221331113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 22480134307684 + 8633177903529 = 4741322^2 + 2938227^2 .

It is a cyclic number.

It is not a de Polignac number, because 31113312211213 - 25 = 31113312211181 is a prime.

It is a super-3 number, since 3×311133122112133 (a number of 41 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31113312211283) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15556656105606 + 15556656105607.

It is an arithmetic number, because the mean of its divisors is an integer number (15556656105607).

Almost surely, 231113312211213 is an apocalyptic number.

It is an amenable number.

31113312211213 is a deficient number, since it is larger than the sum of its proper divisors (1).

31113312211213 is an equidigital number, since it uses as much as digits as its factorization.

31113312211213 is an evil number, because the sum of its binary digits is even.

The product of its digits is 648, while the sum is 25.

Adding to 31113312211213 its reverse (31211221331113), we get a palindrome (62324533542326).

The spelling of 31113312211213 in words is "thirty-one trillion, one hundred thirteen billion, three hundred twelve million, two hundred eleven thousand, two hundred thirteen".