Base | Representation |
---|---|
bin | 1110001001100001010011… |
… | …10011011001010100001001 |
3 | 11002011102020102211101112221 |
4 | 13010300221303121110021 |
5 | 13034230313233243423 |
6 | 150101152525334041 |
7 | 6360605105035012 |
oct | 704605163312411 |
9 | 132142212741487 |
10 | 31113444431113 |
11 | 9a0615728a140 |
12 | 35a5bb1707321 |
13 | 1448ca66b61b5 |
14 | 797c8222c009 |
15 | 38e4eac19e5d |
hex | 1c4c29cd9509 |
31113444431113 has 8 divisors (see below), whose sum is σ = 33941986751520. Its totient is φ = 28284910006080.
The previous prime is 31113444431107. The next prime is 31113444431131.
31113444431113 is nontrivially palindromic in base 10.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31113444431113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (31113444435113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8843281 + ... + 11850337.
It is an arithmetic number, because the mean of its divisors is an integer number (4242748343940).
Almost surely, 231113444431113 is an apocalyptic number.
It is an amenable number.
31113444431113 is a deficient number, since it is larger than the sum of its proper divisors (2828542320407).
31113444431113 is a wasteful number, since it uses less digits than its factorization.
31113444431113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3947687.
The product of its digits is 20736, while the sum is 34.
It can be divided in two parts, 3111344 and 4431113, that added together give a palindrome (7542457).
The spelling of 31113444431113 in words is "thirty-one trillion, one hundred thirteen billion, four hundred forty-four million, four hundred thirty-one thousand, one hundred thirteen".
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