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31114331204011 = 112490952381999
BaseRepresentation
bin1110001001100010111101…
…01010001010100110101011
311002011111112020110010021121
413010301132222022212223
513034234122242012021
6150101420524120111
76360636063343516
oct704613652124653
9132144466403247
1031114331204011
119a065718a7800
1235a61ba696037
1314490b832b1a3
14797d27d03d7d
1538e54d9d2741
hex1c4c5ea8a9ab

31114331204011 has 12 divisors (see below), whose sum is σ = 34207017460000. Its totient is φ = 28279993080240.

The previous prime is 31114331203957. The next prime is 31114331204027. The reversal of 31114331204011 is 11040213341113.

It is not a de Polignac number, because 31114331204011 - 219 = 31114330679723 is a prime.

It is not an unprimeable number, because it can be changed into a prime (31114331204041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 25597011 + ... + 26784988.

Almost surely, 231114331204011 is an apocalyptic number.

31114331204011 is a deficient number, since it is larger than the sum of its proper divisors (3092686255989).

31114331204011 is a wasteful number, since it uses less digits than its factorization.

31114331204011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 52386930 (or 52386919 counting only the distinct ones).

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 31114331204011 its reverse (11040213341113), we get a palindrome (42154544545124).

The spelling of 31114331204011 in words is "thirty-one trillion, one hundred fourteen billion, three hundred thirty-one million, two hundred four thousand, eleven".

Divisors: 1 11 121 4909 53999 593989 52381999 576201989 6338221879 257143233091 2828575564001 31114331204011