Base | Representation |
---|---|
bin | 1110001001101101100010… |
… | …10001100001011001010111 |
3 | 11002012001012011021122010212 |
4 | 13010312301101201121113 |
5 | 13034332241112014431 |
6 | 150104200344040035 |
7 | 6361226625234362 |
oct | 704666121413127 |
9 | 132161164248125 |
10 | 31120012219991 |
11 | 9a08a17668132 |
12 | 35a732516301b |
13 | 14497b22b02c6 |
14 | 7983065db0d9 |
15 | 38e78260b72b |
hex | 1c4db1461657 |
31120012219991 has 2 divisors, whose sum is σ = 31120012219992. Its totient is φ = 31120012219990.
The previous prime is 31120012219963. The next prime is 31120012220039. The reversal of 31120012219991 is 19991221002113.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31120012219991 - 214 = 31120012203607 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31120012219091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15560006109995 + 15560006109996.
It is an arithmetic number, because the mean of its divisors is an integer number (15560006109996).
Almost surely, 231120012219991 is an apocalyptic number.
31120012219991 is a deficient number, since it is larger than the sum of its proper divisors (1).
31120012219991 is an equidigital number, since it uses as much as digits as its factorization.
31120012219991 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17496, while the sum is 41.
The spelling of 31120012219991 in words is "thirty-one trillion, one hundred twenty billion, twelve million, two hundred nineteen thousand, nine hundred ninety-one".
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