Base | Representation |
---|---|
bin | 1110001001101101110001… |
… | …00000010101001000000010 |
3 | 11002012001111121120110012111 |
4 | 13010312320200111020002 |
5 | 13034333013141324102 |
6 | 150104220400245534 |
7 | 6361232630404132 |
oct | 704667040251002 |
9 | 132161447513174 |
10 | 31120133542402 |
11 | 9a08a7a0a2493 |
12 | 35a73599108aa |
13 | 144980147b108 |
14 | 79831877cac2 |
15 | 38e78d0c3cd7 |
hex | 1c4db8815202 |
31120133542402 has 4 divisors (see below), whose sum is σ = 46680200313606. Its totient is φ = 15560066771200.
The previous prime is 31120133542387. The next prime is 31120133542409. The reversal of 31120133542402 is 20424533102113.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 23228534520801 + 7891599021601 = 4819599^2 + 2809199^2 .
It is not an unprimeable number, because it can be changed into a prime (31120133542409) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7780033385599 + ... + 7780033385602.
Almost surely, 231120133542402 is an apocalyptic number.
31120133542402 is a deficient number, since it is larger than the sum of its proper divisors (15560066771204).
31120133542402 is a wasteful number, since it uses less digits than its factorization.
31120133542402 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15560066771203.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 31120133542402 its reverse (20424533102113), we get a palindrome (51544666644515).
The spelling of 31120133542402 in words is "thirty-one trillion, one hundred twenty billion, one hundred thirty-three million, five hundred forty-two thousand, four hundred two".
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