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3112022003113 is a prime number
BaseRepresentation
bin101101010010010010111…
…101110100110110101001
3102000111200011102122122101
4231102102331310312221
5401441410113044423
610341350531453401
7440556543400252
oct55222275646651
912014604378571
103112022003113
11a9a88a321741
12423169a57261
13197601c0924a
14aa8a0861b29
1555e3e0e87ad
hex2d492f74da9

3112022003113 has 2 divisors, whose sum is σ = 3112022003114. Its totient is φ = 3112022003112.

The previous prime is 3112022003053. The next prime is 3112022003131. The reversal of 3112022003113 is 3113002202113.

Together with next prime (3112022003131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3108828396969 + 3193606144 = 1763187^2 + 56512^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3112022003113 is a prime.

It is not a weakly prime, because it can be changed into another prime (3112022003213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556011001556 + 1556011001557.

It is an arithmetic number, because the mean of its divisors is an integer number (1556011001557).

Almost surely, 23112022003113 is an apocalyptic number.

It is an amenable number.

3112022003113 is a deficient number, since it is larger than the sum of its proper divisors (1).

3112022003113 is an equidigital number, since it uses as much as digits as its factorization.

3112022003113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 3112022003113 its reverse (3113002202113), we get a palindrome (6225024205226).

The spelling of 3112022003113 in words is "three trillion, one hundred twelve billion, twenty-two million, three thousand, one hundred thirteen".