3112042140131 has 8 divisors (see below), whose sum is σ = 3114916406784. Its totient is φ = 3109169082240.

The previous prime is 3112042140127. The next prime is 3112042140149. The reversal of 3112042140131 is 1310412402113.

3112042140131 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 3112042140131 - 2² = 3112042140127 is a prime.

It is a super-2 number, since 2×3112042140131² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3112042140097 and 3112042140106.

It is not an unprimeable number, because it can be changed into a prime (3112042640131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4890425 + ... + 5490021.

It is an arithmetic number, because the mean of its divisors is an integer number (389364550848).

Almost surely, 2^{3112042140131} is an apocalyptic number.

3112042140131 is a deficient number, since it is larger than the sum of its proper divisors (2874266653).

3112042140131 is a wasteful number, since it uses less digits than its factorization.

3112042140131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 604381.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 3112042140131 its reverse (1310412402113), we get a palindrome (4422454542244).

The spelling of 3112042140131 in words is "three trillion, one hundred twelve billion, forty-two million, one hundred forty thousand, one hundred thirty-one".