31120434113 has 4 divisors (see below), whose sum is σ = 31120840128. Its totient is φ = 31120028100.

The previous prime is 31120434047. The next prime is 31120434127. The reversal of 31120434113 is 31143402113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 31120434113 - 2⁸ = 31120433857 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (31120434173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49181 + ... + 254282.

It is an arithmetic number, because the mean of its divisors is an integer number (7780210032).

Almost surely, 2^31120434113 is an apocalyptic number.

It is an amenable number.

31120434113 is a deficient number, since it is larger than the sum of its proper divisors (406015).

31120434113 is a wasteful number, since it uses less digits than its factorization.

31120434113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 406014.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 31120434113 its reverse (31143402113), we get a palindrome (62263836226).

The spelling of 31120434113 in words is "thirty-one billion, one hundred twenty million, four hundred thirty-four thousand, one hundred thirteen".