Base | Representation |
---|---|
bin | 100011011000010110111101… |
… | …1110010011110101001111001 |
3 | 1111210220111021111022200222111 |
4 | 1012300231323302132221321 |
5 | 311242340324201144233 |
6 | 3021520224453252321 |
7 | 122360155322322361 |
oct | 10660557362365171 |
9 | 1453814244280874 |
10 | 311211112131193 |
11 | 901859895a522a |
12 | 2aaa296b9340a1 |
13 | 1048610b072aa1 |
14 | 56bc9abbcb9a1 |
15 | 25ea4adccaacd |
hex | 11b0b7bc9ea79 |
311211112131193 has 2 divisors, whose sum is σ = 311211112131194. Its totient is φ = 311211112131192.
The previous prime is 311211112131191. The next prime is 311211112131209. The reversal of 311211112131193 is 391131211112113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 297357329378704 + 13853782752489 = 17244052^2 + 3722067^2 .
It is a cyclic number.
It is not a de Polignac number, because 311211112131193 - 21 = 311211112131191 is a prime.
Together with 311211112131191, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (311211112131191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155605556065596 + 155605556065597.
It is an arithmetic number, because the mean of its divisors is an integer number (155605556065597).
Almost surely, 2311211112131193 is an apocalyptic number.
It is an amenable number.
311211112131193 is a deficient number, since it is larger than the sum of its proper divisors (1).
311211112131193 is an equidigital number, since it uses as much as digits as its factorization.
311211112131193 is an evil number, because the sum of its binary digits is even.
The product of its digits is 972, while the sum is 31.
The spelling of 311211112131193 in words is "three hundred eleven trillion, two hundred eleven billion, one hundred twelve million, one hundred thirty-one thousand, one hundred ninety-three".
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