Base | Representation |
---|---|
bin | 1110001001101111100110… |
… | …11110110100001010110101 |
3 | 11002012011001120102011020201 |
4 | 13010313303132310022311 |
5 | 13034342024442013023 |
6 | 150104502504000501 |
7 | 6361266303562123 |
oct | 704676336641265 |
9 | 132164046364221 |
10 | 31121123001013 |
11 | 9a09437676381 |
12 | 35a7595160131 |
13 | 144992b467196 |
14 | 7983add44913 |
15 | 38e7e9dc1bad |
hex | 1c4df37b42b5 |
31121123001013 has 2 divisors, whose sum is σ = 31121123001014. Its totient is φ = 31121123001012.
The previous prime is 31121123000999. The next prime is 31121123001037. The reversal of 31121123001013 is 31010032112113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 21911555036484 + 9209567964529 = 4680978^2 + 3034727^2 .
It is a cyclic number.
It is not a de Polignac number, because 31121123001013 - 233 = 31112533066421 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31121123001313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15560561500506 + 15560561500507.
It is an arithmetic number, because the mean of its divisors is an integer number (15560561500507).
Almost surely, 231121123001013 is an apocalyptic number.
It is an amenable number.
31121123001013 is a deficient number, since it is larger than the sum of its proper divisors (1).
31121123001013 is an equidigital number, since it uses as much as digits as its factorization.
31121123001013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 31121123001013 its reverse (31010032112113), we get a palindrome (62131155113126).
The spelling of 31121123001013 in words is "thirty-one trillion, one hundred twenty-one billion, one hundred twenty-three million, one thousand, thirteen".
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