Base | Representation |
---|---|
bin | 11100111110111101… |
… | …101100100111110110 |
3 | 2222022212220022101100 |
4 | 130332331230213312 |
5 | 1002214002211042 |
6 | 22144041510530 |
7 | 2151132154221 |
oct | 347675544766 |
9 | 88285808340 |
10 | 31121132022 |
11 | 12220082122 |
12 | 60464a2446 |
13 | 2c1c734526 |
14 | 17132c85b8 |
15 | c2228624c |
hex | 73ef6c9f6 |
31121132022 has 12 divisors (see below), whose sum is σ = 67429119420. Its totient is φ = 10373710668.
The previous prime is 31121132017. The next prime is 31121132069. The reversal of 31121132022 is 22023112113.
31121132022 is a `hidden beast` number, since 311 + 2 + 11 + 320 + 22 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18), and also a Moran number because the ratio is a prime number: 1728951779 = 31121132022 / (3 + 1 + 1 + 2 + 1 + 1 + 3 + 2 + 0 + 2 + 2).
It is a junction number, because it is equal to n+sod(n) for n = 31121131986 and 31121132004.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 864475872 + ... + 864475907.
It is an arithmetic number, because the mean of its divisors is an integer number (5619093285).
Almost surely, 231121132022 is an apocalyptic number.
31121132022 is an abundant number, since it is smaller than the sum of its proper divisors (36307987398).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31121132022 is a wasteful number, since it uses less digits than its factorization.
31121132022 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1728951787 (or 1728951784 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 31121132022 its reverse (22023112113), we get a palindrome (53144244135).
The spelling of 31121132022 in words is "thirty-one billion, one hundred twenty-one million, one hundred thirty-two thousand, twenty-two".
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