3112121112131 has 2 divisors, whose sum is σ = 3112121112132. Its totient is φ = 3112121112130.

The previous prime is 3112121112119. The next prime is 3112121112203. The reversal of 3112121112131 is 1312111212113.

It is a m-pointer prime, because the next prime (3112121112203) can be obtained adding 3112121112131 to its product of digits (72).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 3112121112131 - 2³⁸ = 2837243205187 is a prime.

It is a super-2 number, since 2×3112121112131² (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3112121142131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556060556065 + 1556060556066.

It is an arithmetic number, because the mean of its divisors is an integer number (1556060556066).

Almost surely, 2^{3112121112131} is an apocalyptic number.

3112121112131 is a deficient number, since it is larger than the sum of its proper divisors (1).

3112121112131 is an equidigital number, since it uses as much as digits as its factorization.

3112121112131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 72, while the sum is 20.

Adding to 3112121112131 its reverse (1312111212113), we get a palindrome (4424232324244).

The spelling of 3112121112131 in words is "three trillion, one hundred twelve billion, one hundred twenty-one million, one hundred twelve thousand, one hundred thirty-one".