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311212112014 = 2155606056007
BaseRepresentation
bin1001000011101011010…
…11111111100010001110
31002202021220111022222001
410201311223333202032
520044330300041024
6354545135342514
731325061206506
oct4416553774216
91082256438861
10311212112014
1110aa9113aa81
1250394381a3a
132346899150b
14110c4268a06
158166b9b244
hex4875aff88e

311212112014 has 4 divisors (see below), whose sum is σ = 466818168024. Its totient is φ = 155606056006.

The previous prime is 311212111943. The next prime is 311212112087. The reversal of 311212112014 is 410211212113.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 311212111982 and 311212112000.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77803028002 + ... + 77803028005.

It is an arithmetic number, because the mean of its divisors is an integer number (116704542006).

Almost surely, 2311212112014 is an apocalyptic number.

311212112014 is a deficient number, since it is larger than the sum of its proper divisors (155606056010).

311212112014 is a wasteful number, since it uses less digits than its factorization.

311212112014 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 155606056009.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 311212112014 its reverse (410211212113), we get a palindrome (721423324127).

The spelling of 311212112014 in words is "three hundred eleven billion, two hundred twelve million, one hundred twelve thousand, fourteen".

Divisors: 1 2 155606056007 311212112014