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311212112153 is a prime number
BaseRepresentation
bin1001000011101011010…
…11111111100100011001
31002202021220111100011012
410201311223333210121
520044330300042103
6354545135343305
731325061210065
oct4416553774431
91082256440135
10311212112153
1110aa91140098
1250394381b35
13234689915b7
14110c4268aa5
158166b9b2d8
hex4875aff919

311212112153 has 2 divisors, whose sum is σ = 311212112154. Its totient is φ = 311212112152.

The previous prime is 311212112087. The next prime is 311212112173. The reversal of 311212112153 is 351211212113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 304215124249 + 6996987904 = 551557^2 + 83648^2 .

It is an emirp because it is prime and its reverse (351211212113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 311212112153 - 218 = 311211850009 is a prime.

It is not a weakly prime, because it can be changed into another prime (311212112173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155606056076 + 155606056077.

It is an arithmetic number, because the mean of its divisors is an integer number (155606056077).

Almost surely, 2311212112153 is an apocalyptic number.

It is an amenable number.

311212112153 is a deficient number, since it is larger than the sum of its proper divisors (1).

311212112153 is an equidigital number, since it uses as much as digits as its factorization.

311212112153 is an evil number, because the sum of its binary digits is even.

The product of its digits is 360, while the sum is 23.

Adding to 311212112153 its reverse (351211212113), we get a palindrome (662423324266).

The spelling of 311212112153 in words is "three hundred eleven billion, two hundred twelve million, one hundred twelve thousand, one hundred fifty-three".