Base | Representation |
---|---|
bin | 1001000011101011011… |
… | …11111000011000100101 |
3 | 1002202021222102010011102 |
4 | 10201311233320120211 |
5 | 20044331030200201 |
6 | 354545213245445 |
7 | 31325102653262 |
oct | 4416557703045 |
9 | 1082258363142 |
10 | 311213131301 |
11 | 10aa91776866 |
12 | 50394793885 |
13 | 23468c5a447 |
14 | 110c4452269 |
15 | 8166ced26b |
hex | 4875bf8625 |
311213131301 has 2 divisors, whose sum is σ = 311213131302. Its totient is φ = 311213131300.
The previous prime is 311213131297. The next prime is 311213131331. The reversal of 311213131301 is 103131312113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 310080808801 + 1132322500 = 556849^2 + 33650^2 .
It is a cyclic number.
It is not a de Polignac number, because 311213131301 - 22 = 311213131297 is a prime.
It is a super-2 number, since 2×3112131313012 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311213131331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155606565650 + 155606565651.
It is an arithmetic number, because the mean of its divisors is an integer number (155606565651).
Almost surely, 2311213131301 is an apocalyptic number.
It is an amenable number.
311213131301 is a deficient number, since it is larger than the sum of its proper divisors (1).
311213131301 is an equidigital number, since it uses as much as digits as its factorization.
311213131301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 311213131301 its reverse (103131312113), we get a palindrome (414344443414).
The spelling of 311213131301 in words is "three hundred eleven billion, two hundred thirteen million, one hundred thirty-one thousand, three hundred one".
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