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31121315200049 is a prime number
BaseRepresentation
bin1110001001101111111101…
…11011111111110000110001
311002012011112222001212202112
413010313332323333300301
513034342423142400144
6150104533531255105
76361304126336144
oct704677673776061
9132164488055675
1031121315200049
119a09526110358
1235a76295aa495
13144995c21c819
147983cb69605b
1538e80bbd999e
hex1c4dfeeffc31

31121315200049 has 2 divisors, whose sum is σ = 31121315200050. Its totient is φ = 31121315200048.

The previous prime is 31121315200009. The next prime is 31121315200109. The reversal of 31121315200049 is 94000251312113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 31068751384225 + 52563815824 = 5573935^2 + 229268^2 .

It is a cyclic number.

It is not a de Polignac number, because 31121315200049 - 240 = 30021803572273 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 31121315199988 and 31121315200024.

It is not a weakly prime, because it can be changed into another prime (31121315200009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15560657600024 + 15560657600025.

It is an arithmetic number, because the mean of its divisors is an integer number (15560657600025).

Almost surely, 231121315200049 is an apocalyptic number.

It is an amenable number.

31121315200049 is a deficient number, since it is larger than the sum of its proper divisors (1).

31121315200049 is an equidigital number, since it uses as much as digits as its factorization.

31121315200049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6480, while the sum is 32.

The spelling of 31121315200049 in words is "thirty-one trillion, one hundred twenty-one billion, three hundred fifteen million, two hundred thousand, forty-nine".