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94000251312113 = 412347976859419
BaseRepresentation
bin10101010111111000100011…
…100101101001011111110001
3110022211100002010122221210112
4111113320203211221133301
544310100003313441423
6531531041434111105
725541202566556326
oct2527704345513761
9408740063587715
1094000251312113
1127a51312314293
12a661a65b7b495
13405b254b97b53
14192d8ca560b4d
15ad0267929a78
hex557e239697f1

94000251312113 has 8 divisors (see below), whose sum is σ = 96333968562720. Its totient is φ = 91668487785120.

The previous prime is 94000251312049. The next prime is 94000251312131. The reversal of 94000251312113 is 31121315200049.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 94000251312113 - 26 = 94000251312049 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 94000251312113.

It is not an unprimeable number, because it can be changed into a prime (94000251312193) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 488333483 + ... + 488525936.

It is an arithmetic number, because the mean of its divisors is an integer number (12041746070340).

Almost surely, 294000251312113 is an apocalyptic number.

It is an amenable number.

94000251312113 is a deficient number, since it is larger than the sum of its proper divisors (2333717250607).

94000251312113 is a wasteful number, since it uses less digits than its factorization.

94000251312113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 976861807.

The product of its (nonzero) digits is 6480, while the sum is 32.

The spelling of 94000251312113 in words is "ninety-four trillion, two hundred fifty-one million, three hundred twelve thousand, one hundred thirteen".

Divisors: 1 41 2347 96227 976859419 40051236179 2292689056393 94000251312113