Base | Representation |
---|---|
bin | 101101010010011001100… |
… | …010101100100111100000 |
3 | 102000111221212000221102110 |
4 | 231102121202230213200 |
5 | 401442121334111000 |
6 | 10341405512315320 |
7 | 440562353231646 |
oct | 55223142544740 |
9 | 12014855027373 |
10 | 3112132332000 |
11 | a9a93662843a |
12 | 42319a9a2b40 |
13 | 19761ba28203 |
14 | aa8b1381196 |
15 | 55e48b3d850 |
hex | 2d4998ac9e0 |
3112132332000 has 192 divisors, whose sum is σ = 10546910337600. Its totient is φ = 801284556800.
The previous prime is 3112132331999. The next prime is 3112132332011. The reversal of 3112132332000 is 2332312113.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4123455 + ... + 4819454.
It is an arithmetic number, because the mean of its divisors is an integer number (54931824675).
Almost surely, 23112132332000 is an apocalyptic number.
3112132332000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
3112132332000 is an abundant number, since it is smaller than the sum of its proper divisors (7434778005600).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3112132332000 is a wasteful number, since it uses less digits than its factorization.
3112132332000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8942966 (or 8942948 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 3112132332000 its reverse (2332312113), we get a palindrome (3114464644113).
The spelling of 3112132332000 in words is "three trillion, one hundred twelve billion, one hundred thirty-two million, three hundred thirty-two thousand".
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