Base | Representation |
---|---|
bin | 11100111110111110… |
… | …011111111110000101 |
3 | 2222022220021222212221 |
4 | 130332332133332011 |
5 | 1002214030423331 |
6 | 22144050212341 |
7 | 2151134021335 |
oct | 347676377605 |
9 | 88286258787 |
10 | 31121342341 |
11 | 12220206141 |
12 | 60465840b1 |
13 | 2c1c7a918b |
14 | 17133410c5 |
15 | c222c8711 |
hex | 73ef9ff85 |
31121342341 has 2 divisors, whose sum is σ = 31121342342. Its totient is φ = 31121342340.
The previous prime is 31121342309. The next prime is 31121342359. The reversal of 31121342341 is 14324312113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 24708696100 + 6412646241 = 157190^2 + 80079^2 .
It is a cyclic number.
It is not a de Polignac number, because 31121342341 - 25 = 31121342309 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31121342641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15560671170 + 15560671171.
It is an arithmetic number, because the mean of its divisors is an integer number (15560671171).
Almost surely, 231121342341 is an apocalyptic number.
It is an amenable number.
31121342341 is a deficient number, since it is larger than the sum of its proper divisors (1).
31121342341 is an equidigital number, since it uses as much as digits as its factorization.
31121342341 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1728, while the sum is 25.
Adding to 31121342341 its reverse (14324312113), we get a palindrome (45445654454).
The spelling of 31121342341 in words is "thirty-one billion, one hundred twenty-one million, three hundred forty-two thousand, three hundred forty-one".
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