3112140412113 has 4 divisors (see below), whose sum is σ = 4149520549488. Its totient is φ = 2074760274740.

The previous prime is 3112140412097. The next prime is 3112140412133.

3112140412113 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3112140412113 - 2⁴ = 3112140412097 is a prime.

It is not an unprimeable number, because it can be changed into a prime (3112140412133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 518690068683 + ... + 518690068688.

It is an arithmetic number, because the mean of its divisors is an integer number (1037380137372).

Almost surely, 2^{3112140412113} is an apocalyptic number.

It is an amenable number.

3112140412113 is a deficient number, since it is larger than the sum of its proper divisors (1037380137375).

3112140412113 is a wasteful number, since it uses less digits than its factorization.

3112140412113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1037380137374.

The product of its (nonzero) digits is 576, while the sum is 24.

It can be divided in two parts, 3112140 and 412113, that added together give a palindrome (3524253).

The spelling of 3112140412113 in words is "three trillion, one hundred twelve billion, one hundred forty million, four hundred twelve thousand, one hundred thirteen".