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3112144344431 is a prime number
BaseRepresentation
bin101101010010011010010…
…000100001010101101111
3102000111222200122020101022
4231102122100201111233
5401442132423010211
610341411022004355
7440562560312423
oct55223220412557
912014880566338
103112144344431
11a9a942392571
124231a2a166bb
13197621372a65
14aa8b2bcab83
1555e49c12bdb
hex2d49a42156f

3112144344431 has 2 divisors, whose sum is σ = 3112144344432. Its totient is φ = 3112144344430.

The previous prime is 3112144344403. The next prime is 3112144344437. The reversal of 3112144344431 is 1344434412113.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3112144344431 is a prime.

It is a super-2 number, since 2×31121443444312 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3112144344391 and 3112144344400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3112144344437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556072172215 + 1556072172216.

It is an arithmetic number, because the mean of its divisors is an integer number (1556072172216).

Almost surely, 23112144344431 is an apocalyptic number.

3112144344431 is a deficient number, since it is larger than the sum of its proper divisors (1).

3112144344431 is an equidigital number, since it uses as much as digits as its factorization.

3112144344431 is an evil number, because the sum of its binary digits is even.

The product of its digits is 55296, while the sum is 35.

Adding to 3112144344431 its reverse (1344434412113), we get a palindrome (4456578756544).

The spelling of 3112144344431 in words is "three trillion, one hundred twelve billion, one hundred forty-four million, three hundred forty-four thousand, four hundred thirty-one".