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311219891041 is a prime number
BaseRepresentation
bin1001000011101100010…
…01101010101101100001
31002202022110010112210011
410201312021222231201
520044334243003131
6354550014204521
731325214266053
oct4416611525541
91082273115704
10311219891041
1110aa95573524
1250396ab3741
132346a4861a7
14110c52d18d3
1581676d60b1
hex487626ab61

311219891041 has 2 divisors, whose sum is σ = 311219891042. Its totient is φ = 311219891040.

The previous prime is 311219891039. The next prime is 311219891051. The reversal of 311219891041 is 140198912113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 246705923025 + 64513968016 = 496695^2 + 253996^2 .

It is a cyclic number.

It is not a de Polignac number, because 311219891041 - 21 = 311219891039 is a prime.

Together with 311219891039, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 311219890985 and 311219891003.

It is not a weakly prime, because it can be changed into another prime (311219891051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155609945520 + 155609945521.

It is an arithmetic number, because the mean of its divisors is an integer number (155609945521).

Almost surely, 2311219891041 is an apocalyptic number.

It is an amenable number.

311219891041 is a deficient number, since it is larger than the sum of its proper divisors (1).

311219891041 is an equidigital number, since it uses as much as digits as its factorization.

311219891041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 40.

The spelling of 311219891041 in words is "three hundred eleven billion, two hundred nineteen million, eight hundred ninety-one thousand, forty-one".