Base | Representation |
---|---|
bin | 1110001001110001011100… |
… | …11011111011011011000000 |
3 | 11002012020121111120121000201 |
4 | 13010320232123323123000 |
5 | 13034401041144200112 |
6 | 150105144555454544 |
7 | 6361332644021542 |
oct | 704705633733300 |
9 | 132166544517021 |
10 | 31122112100032 |
11 | 9a098a4a24088 |
12 | 35a7810457454 |
13 | 1449a58358685 |
14 | 798465455692 |
15 | 38e856b4d257 |
hex | 1c4e2e6fb6c0 |
31122112100032 has 56 divisors (see below), whose sum is σ = 62156527964064. Its totient is φ = 15460641411072.
The previous prime is 31122112100029. The next prime is 31122112100047. The reversal of 31122112100032 is 23000121122113.
It is a super-3 number, since 3×311221121000323 (a number of 41 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 31122112099982 and 31122112100009.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 125445933 + ... + 125693779.
Almost surely, 231122112100032 is an apocalyptic number.
31122112100032 is a gapful number since it is divisible by the number (32) formed by its first and last digit.
It is an amenable number.
31122112100032 is a deficient number, since it is larger than the sum of its proper divisors (31034415864032).
31122112100032 is a wasteful number, since it uses less digits than its factorization.
31122112100032 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 260513 (or 260503 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 31122112100032 its reverse (23000121122113), we get a palindrome (54122233222145).
The spelling of 31122112100032 in words is "thirty-one trillion, one hundred twenty-two billion, one hundred twelve million, one hundred thousand, thirty-two".
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