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311221130230 = 2531399431671
BaseRepresentation
bin1001000011101100011…
…10011001001111110110
31002202022112110111122001
410201312032121033312
520044340102131410
6354550100525514
731325230646623
oct4416616311766
91082275414561
10311221130230
1110aa9623a54a
12503973b089a
132346a7cb23a
14110c553534a
15816787d33a
hex48763993f6

311221130230 has 16 divisors (see below), whose sum is σ = 561987810144. Its totient is φ = 124090724160.

The previous prime is 311221130197. The next prime is 311221130237. The reversal of 311221130230 is 32031122113.

It is a super-3 number, since 3×3112211302303 (a number of 35 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 311221130198 and 311221130207.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (311221130237) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 49712706 + ... + 49718965.

It is an arithmetic number, because the mean of its divisors is an integer number (35124238134).

Almost surely, 2311221130230 is an apocalyptic number.

311221130230 is a deficient number, since it is larger than the sum of its proper divisors (250766679914).

311221130230 is a wasteful number, since it uses less digits than its factorization.

311221130230 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 99431991.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 311221130230 its reverse (32031122113), we get a palindrome (343252252343).

The spelling of 311221130230 in words is "three hundred eleven billion, two hundred twenty-one million, one hundred thirty thousand, two hundred thirty".

Divisors: 1 2 5 10 313 626 1565 3130 99431671 198863342 497158355 994316710 31122113023 62244226046 155610565115 311221130230