Base | Representation |
---|---|
bin | 101101010010011110010… |
… | …010100111000110110010 |
3 | 102000112011101221120000122 |
4 | 231102132102213012302 |
5 | 401442302233014302 |
6 | 10341421440050242 |
7 | 440564341346453 |
oct | 55223622470662 |
9 | 12015141846018 |
10 | 3112212001202 |
11 | a9a9775a3057 |
12 | 423201603982 |
13 | 1976323a0b55 |
14 | aa8bbb9d12a |
15 | 55e50b293a2 |
hex | 2d49e4a71b2 |
3112212001202 has 8 divisors (see below), whose sum is σ = 4677673350000. Its totient is φ = 1552987551204.
The previous prime is 3112212001193. The next prime is 3112212001207. The reversal of 3112212001202 is 2021002122113.
3112212001202 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-3 number, since 3×31122120012023 (a number of 38 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (3112212001207) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1559223452 + ... + 1559225447.
It is an arithmetic number, because the mean of its divisors is an integer number (584709168750).
Almost surely, 23112212001202 is an apocalyptic number.
3112212001202 is a deficient number, since it is larger than the sum of its proper divisors (1565461348798).
3112212001202 is a wasteful number, since it uses less digits than its factorization.
3112212001202 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3118449400.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 3112212001202 its reverse (2021002122113), we get a palindrome (5133214123315).
The spelling of 3112212001202 in words is "three trillion, one hundred twelve billion, two hundred twelve million, one thousand, two hundred two".
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