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3112343110439 is a prime number
BaseRepresentation
bin101101010010100110000…
…110110000001100100111
3102000112111112122121002022
4231102212012300030213
5401443034314013224
610341442442133355
7440600522640233
oct55224606601447
912015445577068
103112343110439
11a9aa346023a2
124232394b125b
131976535b7494
14aa8d136b5c3
1555e5c3c665e
hex2d4a61b0327

3112343110439 has 2 divisors, whose sum is σ = 3112343110440. Its totient is φ = 3112343110438.

The previous prime is 3112343110379. The next prime is 3112343110463. The reversal of 3112343110439 is 9340113432113.

It is a strong prime.

It is an emirp because it is prime and its reverse (9340113432113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3112343110439 - 216 = 3112343044903 is a prime.

It is a super-4 number, since 4×31123431104394 (a number of 51 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3112343110399 and 3112343110408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3112343110339) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556171555219 + 1556171555220.

It is an arithmetic number, because the mean of its divisors is an integer number (1556171555220).

Almost surely, 23112343110439 is an apocalyptic number.

3112343110439 is a deficient number, since it is larger than the sum of its proper divisors (1).

3112343110439 is an equidigital number, since it uses as much as digits as its factorization.

3112343110439 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23328, while the sum is 35.

The spelling of 3112343110439 in words is "three trillion, one hundred twelve billion, three hundred forty-three million, one hundred ten thousand, four hundred thirty-nine".