Base | Representation |
---|---|
bin | 1001000011101110110… |
… | …10010110010110111101 |
3 | 1002202100220221002112121 |
4 | 10201313122112112331 |
5 | 20044410201310331 |
6 | 354552051402541 |
7 | 31325562125536 |
oct | 4416732262675 |
9 | 1082326832477 |
10 | 311241041341 |
11 | 10aaa64aa00a |
12 | 503a1bb3451 |
13 | 23471980069 |
14 | 110c803968d |
15 | 81694b2c11 |
hex | 48776965bd |
311241041341 has 4 divisors (see below), whose sum is σ = 327622148800. Its totient is φ = 294859933884.
The previous prime is 311241041339. The next prime is 311241041407. The reversal of 311241041341 is 143140142113.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 311241041341 - 21 = 311241041339 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (311241041641) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8190553701 + ... + 8190553738.
It is an arithmetic number, because the mean of its divisors is an integer number (81905537200).
Almost surely, 2311241041341 is an apocalyptic number.
It is an amenable number.
311241041341 is a deficient number, since it is larger than the sum of its proper divisors (16381107459).
311241041341 is a wasteful number, since it uses less digits than its factorization.
311241041341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16381107458.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 311241041341 its reverse (143140142113), we get a palindrome (454381183454).
The spelling of 311241041341 in words is "three hundred eleven billion, two hundred forty-one million, forty-one thousand, three hundred forty-one".
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