Base | Representation |
---|---|
bin | 1001000011101110110… |
… | …11000100100000000101 |
3 | 1002202100221021200210121 |
4 | 10201313123010200011 |
5 | 20044410223332331 |
6 | 354552055421541 |
7 | 31325563543546 |
oct | 4416733044005 |
9 | 1082327250717 |
10 | 311241230341 |
11 | 10aaa6619008 |
12 | 503a20848b1 |
13 | 23471a180b2 |
14 | 110c80884cd |
15 | 81694edc11 |
hex | 48776c4805 |
311241230341 has 2 divisors, whose sum is σ = 311241230342. Its totient is φ = 311241230340.
The previous prime is 311241230329. The next prime is 311241230357. The reversal of 311241230341 is 143032142113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 195294170241 + 115947060100 = 441921^2 + 340510^2 .
It is a cyclic number.
It is not a de Polignac number, because 311241230341 - 25 = 311241230309 is a prime.
It is a super-2 number, since 2×3112412303412 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311241230381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155620615170 + 155620615171.
It is an arithmetic number, because the mean of its divisors is an integer number (155620615171).
Almost surely, 2311241230341 is an apocalyptic number.
It is an amenable number.
311241230341 is a deficient number, since it is larger than the sum of its proper divisors (1).
311241230341 is an equidigital number, since it uses as much as digits as its factorization.
311241230341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 311241230341 its reverse (143032142113), we get a palindrome (454273372454).
The spelling of 311241230341 in words is "three hundred eleven billion, two hundred forty-one million, two hundred thirty thousand, three hundred forty-one".
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