Base | Representation |
---|---|
bin | 1110001001110101100011… |
… | …01001001110100000111011 |
3 | 11002012110021220201021211010 |
4 | 13010322301221032200323 |
5 | 13034420043212321103 |
6 | 150110151233205003 |
7 | 6361441333541025 |
oct | 704726151164073 |
9 | 132173256637733 |
10 | 31124313401403 |
11 | 9a0a824562412 |
12 | 35a8125700763 |
13 | 144a019424471 |
14 | 7985d3951015 |
15 | 38e935025903 |
hex | 1c4eb1a4e83b |
31124313401403 has 16 divisors (see below), whose sum is σ = 42264796469760. Its totient is φ = 20367725260896.
The previous prime is 31124313401387. The next prime is 31124313401407. The reversal of 31124313401403 is 30410431342113.
It is not a de Polignac number, because 31124313401403 - 24 = 31124313401387 is a prime.
It is not an unprimeable number, because it can be changed into a prime (31124313401407) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 129749875 + ... + 129989532.
It is an arithmetic number, because the mean of its divisors is an integer number (2641549779360).
Almost surely, 231124313401403 is an apocalyptic number.
31124313401403 is a deficient number, since it is larger than the sum of its proper divisors (11140483068357).
31124313401403 is a wasteful number, since it uses less digits than its factorization.
31124313401403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 259740146.
The product of its (nonzero) digits is 10368, while the sum is 30.
Adding to 31124313401403 its reverse (30410431342113), we get a palindrome (61534744743516).
The spelling of 31124313401403 in words is "thirty-one trillion, one hundred twenty-four billion, three hundred thirteen million, four hundred one thousand, four hundred three".
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