311243323 has 2 divisors, whose sum is σ = 311243324. Its totient is φ = 311243322.

The previous prime is 311243321. The next prime is 311243333. The reversal of 311243323 is 323342113.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 311243323 - 2¹ = 311243321 is a prime.

It is a super-2 number, since 2×311243323² = 193744812224164658, which contains 22 as substring.

Together with 311243321, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 311243294 and 311243303.

It is not a weakly prime, because it can be changed into another prime (311243321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155621661 + 155621662.

It is an arithmetic number, because the mean of its divisors is an integer number (155621662).

Almost surely, 2^311243323 is an apocalyptic number.

311243323 is a deficient number, since it is larger than the sum of its proper divisors (1).

311243323 is an equidigital number, since it uses as much as digits as its factorization.

311243323 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1296, while the sum is 22.

The square root of 311243323 is about 17642.0895304383. The cubic root of 311243323 is about 677.6935431035.

Adding to 311243323 its reverse (323342113), we get a palindrome (634585436).

The spelling of 311243323 in words is "three hundred eleven million, two hundred forty-three thousand, three hundred twenty-three".