Base | Representation |
---|---|
bin | 101101010010101011111… |
… | …000111001101000000111 |
3 | 102000112202022020022211112 |
4 | 231102223320321220013 |
5 | 401443234134023333 |
6 | 10341500225555235 |
7 | 440603111461130 |
oct | 55225370715007 |
9 | 12015668208745 |
10 | 3112440142343 |
11 | a9aa84356954 |
12 | 423265aa5b1b |
13 | 19766a72bccc |
14 | aa9001c8c87 |
15 | 55e65b91948 |
hex | 2d4abe39a07 |
3112440142343 has 4 divisors (see below), whose sum is σ = 3557074448400. Its totient is φ = 2667805836288.
The previous prime is 3112440142283. The next prime is 3112440142363. The reversal of 3112440142343 is 3432410442113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3112440142343 - 214 = 3112440125959 is a prime.
It is a super-2 number, since 2×31124401423432 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3112440142363) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 222317153018 + ... + 222317153031.
It is an arithmetic number, because the mean of its divisors is an integer number (889268612100).
Almost surely, 23112440142343 is an apocalyptic number.
3112440142343 is a deficient number, since it is larger than the sum of its proper divisors (444634306057).
3112440142343 is an equidigital number, since it uses as much as digits as its factorization.
3112440142343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 444634306056.
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 3112440142343 its reverse (3432410442113), we get a palindrome (6544850584456).
The spelling of 3112440142343 in words is "three trillion, one hundred twelve billion, four hundred forty million, one hundred forty-two thousand, three hundred forty-three".
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