Base | Representation |
---|---|
bin | 11100111111001010… |
… | …010101010011110001 |
3 | 2222100010010121010001 |
4 | 130333022111103301 |
5 | 1002220324210101 |
6 | 22144240510001 |
7 | 2151202261261 |
oct | 347712252361 |
9 | 88303117101 |
10 | 31124444401 |
11 | 12221a34826 |
12 | 604761b301 |
13 | 2c2032410b |
14 | 171390b7a1 |
15 | c226dc901 |
hex | 73f2954f1 |
31124444401 has 2 divisors, whose sum is σ = 31124444402. Its totient is φ = 31124444400.
The previous prime is 31124444389. The next prime is 31124444413. The reversal of 31124444401 is 10444442113.
It is a balanced prime because it is at equal distance from previous prime (31124444389) and next prime (31124444413).
It can be written as a sum of positive squares in only one way, i.e., 28701442225 + 2423002176 = 169415^2 + 49224^2 .
It is a cyclic number.
It is not a de Polignac number, because 31124444401 - 217 = 31124313329 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 31124444401.
It is not a weakly prime, because it can be changed into another prime (31124244401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15562222200 + 15562222201.
It is an arithmetic number, because the mean of its divisors is an integer number (15562222201).
Almost surely, 231124444401 is an apocalyptic number.
It is an amenable number.
31124444401 is a deficient number, since it is larger than the sum of its proper divisors (1).
31124444401 is an equidigital number, since it uses as much as digits as its factorization.
31124444401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6144, while the sum is 28.
Adding to 31124444401 its reverse (10444442113), we get a palindrome (41568886514).
The spelling of 31124444401 in words is "thirty-one billion, one hundred twenty-four million, four hundred forty-four thousand, four hundred one".
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