311249473919 has 4 divisors (see below), whose sum is σ = 311278939344. Its totient is φ = 311220008496.

The previous prime is 311249473867. The next prime is 311249473933. The reversal of 311249473919 is 919374942113.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 919374942113 = 53 ⋅17346697021.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-311249473919 is a prime.

It is a super-2 number, since 2×311249473919² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (311249473999) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14716862 + ... + 14737995.

It is an arithmetic number, because the mean of its divisors is an integer number (77819734836).

Almost surely, 2^311249473919 is an apocalyptic number.

311249473919 is a deficient number, since it is larger than the sum of its proper divisors (29465425).

311249473919 is a wasteful number, since it uses less digits than its factorization.

311249473919 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29465424.

The product of its digits is 1469664, while the sum is 53.

The spelling of 311249473919 in words is "three hundred eleven billion, two hundred forty-nine million, four hundred seventy-three thousand, nine hundred nineteen".